Remainder sequence

//Program to find the number which leaves remainder 9 when divided by 10,remainder 8 when divided by 9,remainder 7 when divided by 8,remainder 6 when divided by 7,remainder 5 when divided by 6,remainder 4 when divided by 5,remainder 3 when divided by 4,remainder 2 when divided by 3 and remainder 1 when divided by 2.

#include<iostream>
#include<conio.h>
using namespace std;
main()
{
      int flag=1,number=1;
      while(flag)
      {
        if((number%10)==9)
        if((number%9)==8)
        if((number%8)==7)
        if((number%7)==6)
        if((number%6)==5)
        if((number%5)==4)
        if((number%4)==3)
        if((number%3)==2)
        if((number%2)==1)
         {
             cout<<"\n number :"<<number;
             flag=0;                
          }
        number++;        
      }
      getch();
   }